Answer
$stress = 1.3\times 10^7~N/m^2$
Work Step by Step
We can find the stress:
$stress = \frac{F}{A}$
$stress = \frac{mg}{\pi~r^2}$
$stress = \frac{(95~kg)(9.8~m/s^2)}{(\pi)~(4.8\times 10^{-3}~m)^2}$
$stress = 1.3\times 10^7~N/m^2$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 12 - Equilibrium and Elasticity - Problems - Page 350: 52b
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