Answer
1.9$\times10^{-3}$
Work Step by Step
$L = 15 m$
$\Delta L = 2.8 cm =2.8\times 10^{-2}$m
Strain = $\frac{\Delta L}{L}$ = $\frac{2.8\times10^{-2}m}{15m} \approx 1.9\times10^{-3}$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 12 - Equilibrium and Elasticity - Problems - Page 350: 52a
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