Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 9 - Section 9.5 - Totally Inelastic Collisions - Example: 9.8

Answer

The answer is below.

Work Step by Step

We find the x and y components of the velocity: $v_{fx} = \frac{m_1v_{1x} + m_2v_{2x} }{m_1+m_2}=\frac{2 \times 3.5 + 2 \times .689 }{2+2} = 2.14 \ Mm/s $ $v_{fy} = \frac{m_1v_{1y} + m_2v_{2y} }{m_1+m_2}=\frac{0 + 2 \times 1.62 }{2+2} = .809 \ Mm/s $
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