Answer
The answer is below.
Work Step by Step
We find the x and y components of the velocity:
$v_{fx} = \frac{m_1v_{1x} + m_2v_{2x} }{m_1+m_2}=\frac{2 \times 3.5 + 2 \times .689 }{2+2} = 2.14 \ Mm/s $
$v_{fy} = \frac{m_1v_{1y} + m_2v_{2y} }{m_1+m_2}=\frac{0 + 2 \times 1.62 }{2+2} = .809 \ Mm/s $
