Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 9 - Section 9.5 - Totally Inelastic Collisions - Example: 9.7

Answer

$49 \ m/s$

Work Step by Step

We find: $v_p = \frac{(m_p+m_c)v_c}{m_p} = (.16+6.4)(1.2)/.16 \approx 49 \ m/s$
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