Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 9 - Exercises and Problems: 30

Answer

$v_d=10.9i+26.7j \frac{m}{s}$

Work Step by Step

We know that the total energy is conserved $\implies m_nv_n+m_dv_d=m_tv_t$ This can be rearranged as: $v_d=\frac{m_tv_t-m_nv_n}{m_d}$ We plug in the known values to obtain: $v_d=\frac{3.02(15.1i+22.6j)-1.01(23.5i+14.4j)}{2.010}$ $v_d=10.9i+26.7j \frac{m}{s}$
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