## Essential University Physics: Volume 1 (3rd Edition)

$v_d=10.9i+26.7j \frac{m}{s}$
We know that the total energy is conserved $\implies m_nv_n+m_dv_d=m_tv_t$ This can be rearranged as: $v_d=\frac{m_tv_t-m_nv_n}{m_d}$ We plug in the known values to obtain: $v_d=\frac{3.02(15.1i+22.6j)-1.01(23.5i+14.4j)}{2.010}$ $v_d=10.9i+26.7j \frac{m}{s}$