Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 9 - Exercises and Problems: 26

Answer

Please see the work below.

Work Step by Step

(a) We know that $F=ma$ We plug in the known values to obtain: $F=220\times 10^{-9}\times 980$ $F=2.156\times 10^{-4}N$ (b) We can find the impulse as $I=F\Delta t$ We plug in the known values to obtain: $I=(2.156\times 10^{-7})(1.2\times 10^{-3})$ $I=2.6\times 10^{-7}Ns$ (c) We know that change in momentum=Impulse $\implies \Delta P=2.6\times 10^{-7}\frac{Kg\space m}{s}$
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