# Chapter 8 - Section 8.3 - Orbital Motion - Example: 8.3

$4.22 \times 10^7 \ m$

#### Work Step by Step

We solve the equation for the period of the orbit for r to find: $r = (\frac{GM_ET^2}{4\pi^2})^{1/3} = (\frac{6.67\times10^{-11}\times5.97 \times 10^{24}(8.64 \times 10^4)^2}{4\pi^2})^{1/3} = 4.22 \times 10^7 \ m$

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