Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 8 - Section 8.3 - Orbital Motion - Example: 8.3

Answer

$4.22 \times 10^7 \ m$

Work Step by Step

We solve the equation for the period of the orbit for r to find: $r = (\frac{GM_ET^2}{4\pi^2})^{1/3} = (\frac{6.67\times10^{-11}\times5.97 \times 10^{24}(8.64 \times 10^4)^2}{4\pi^2})^{1/3} = 4.22 \times 10^7 \ m$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.