Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 8 - Section 8.3 - Orbital Motion - Example: 8.2

Answer

$7.68 \ km/s$

Work Step by Step

We use the equation for the velocity to find: $v = \sqrt{\frac{GM_E}{r}} = \sqrt{\frac{(6.67\times10^{-11}\times5.97 \times 10^{24})}{6.37\times10^6 + 380 \times 10^3}} = 7.68 \ km/s$
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