Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 7 - Exercises and Problems - Page 127: 52


Please see the work below.

Work Step by Step

We know that $U=mgh$ We plug in the known values to obtain: $U=(8.5\times 10^9)(9.8)(140)=1.166\times 10^{13}J$ We can find the electricity as $E=Pt$ We plug in the known values to obtain: $E=(330\times 10^6)(8.0\times 3600)=9.504\times 10^{12}J$ The efficiency is given as: $\epsilon=\frac{E}{U}\times 100=\frac{9.504\times 10^{12}}{1.166\times 10^{13}}\times 100=81\%$
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