Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 7 - Exercises and Problems: 50

Answer

Please see the work below.

Work Step by Step

We know that in equilibrium position $\frac{dU}{dr}=0$ $\implies \frac{-nb}{r^{n+1}}-\frac{-a}{r^2}=0$ This can be rearranged as: $a-\frac{nb}{r^{n-1}}=0$ $\implies \frac{nb}{r^{n-1}}=a$ $r^{n-1}=\frac{nb}{a}$ $r=\sqrt[n-1] \frac{nb}{a}$ $ r = 2.82 \times 10 ^ {-10} m $
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