Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 6 - Exercises and Problems: 66

Answer

Please see the work below.

Work Step by Step

We know that $P=\frac{mgh}{t}$ This can be rearranged as: $\frac{m}{t}=\frac{P}{gh}$ We plug in the known values to obtain: $\frac{m}{t}=\frac{(0.5hp)}{(60m)(9.8\frac{m}{s^2})}=\frac{(0.5hp)(746\frac{W}{hp})}{(60m)(9.8\frac{m}{s^2})}=0.63\frac{Kg}{s} = 10.1 \frac{gal}{min}$
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