Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 6 - Exercises and Problems: 65

Answer

Please see the work below.

Work Step by Step

We know that $cos(\theta)=\frac{A.B}{|A||B|}$ $cos(\theta)=\frac{(\frac{1}{3})|A|^2}{|A||A|}=\frac{1}{3}$ Now we can find the angle as $\theta=cos^{-1}(\frac{1}{3})=71^{\circ}$
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