## Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson

# Chapter 6 - Exercises and Problems - Page 106: 65

#### Answer

Please see the work below.

#### Work Step by Step

We know that $cos(\theta)=\frac{A.B}{|A||B|}$ $cos(\theta)=\frac{(\frac{1}{3})|A|^2}{|A||A|}=\frac{1}{3}$ Now we can find the angle as $\theta=cos^{-1}(\frac{1}{3})=71^{\circ}$

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