Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 5 - Section 5.1 - Using Newton’s Second Law - Example - Page 73: 5.3


350 Newtons

Work Step by Step

Once again, we begin by considering the x and y components: x: $ -F_h + F_nsin\theta=0$ y: $F_ncos\theta -mg =0 \\ F_n= \frac{mg}{cos\theta}$ We plug in the result from the y equation into the x equation to find: $F_h = \frac{mg}{cos\theta} \times sin\theta = mgtan\theta = (62)(9.81)(tan30^{\circ}) \approx 350N$
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