Answer
350 Newtons
Work Step by Step
Once again, we begin by considering the x and y components:
x: $ -F_h + F_nsin\theta=0$
y: $F_ncos\theta -mg =0 \\ F_n= \frac{mg}{cos\theta}$
We plug in the result from the y equation into the x equation to find:
$F_h = \frac{mg}{cos\theta} \times sin\theta = mgtan\theta = (62)(9.81)(tan30^{\circ}) \approx 350N$
