## Essential University Physics: Volume 1 (3rd Edition)

Once again, we begin by considering the x and y components: x: $-F_h + F_nsin\theta=0$ y: $F_ncos\theta -mg =0 \\ F_n= \frac{mg}{cos\theta}$ We plug in the result from the y equation into the x equation to find: $F_h = \frac{mg}{cos\theta} \times sin\theta = mgtan\theta = (62)(9.81)(tan30^{\circ}) \approx 350N$