## Essential University Physics: Volume 1 (3rd Edition)

We find the two components of the forces: x: $- T_2cos\theta + T_1 cos\theta=0$ y: $T_1 sin\theta - mg + T_2sin\theta=0$ We see that the two y tensions are equal, so we obtain: $2Tsin\theta - mg = 0 \\ T = \frac{mg}{2sin\theta}= \frac{17 \times 9.81}{2sin22^{\circ}}= 220\ N$