Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 5 - Section 5.1 - Using Newton’s Second Law - Example - Page 73: 5.2


220 Newtons

Work Step by Step

We find the two components of the forces: x: $- T_2cos\theta + T_1 cos\theta=0$ y: $T_1 sin\theta - mg + T_2sin\theta=0$ We see that the two y tensions are equal, so we obtain: $2Tsin\theta - mg = 0 \\ T = \frac{mg}{2sin\theta}= \frac{17 \times 9.81}{2sin22^{\circ}}= 220\ N$
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