Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 16 - Exercises and Problems - Page 301: 74


2.92 Joules

Work Step by Step

We know the following equation: $ Q = \int mCdt$ Thus, we find: $ Q = \int_{10}^{25} 40 (31)(\frac{T}{343})^3 dT $ Evaluating this integral gives: $ Q = 2.92 J$
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