## Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson

# Chapter 16 - Exercises and Problems - Page 301: 74

2.92 Joules

#### Work Step by Step

We know the following equation: $Q = \int mCdt$ Thus, we find: $Q = \int_{10}^{25} 40 (31)(\frac{T}{343})^3 dT$ Evaluating this integral gives: $Q = 2.92 J$

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