Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 16 - Exercises and Problems - Page 301: 74

Answer

2.92 Joules

Work Step by Step

We know the following equation: $ Q = \int mCdt$ Thus, we find: $ Q = \int_{10}^{25} 40 (31)(\frac{T}{343})^3 dT $ Evaluating this integral gives: $ Q = 2.92 J$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.