Answer
a) 1200 K
b) 700 K
Work Step by Step
a) We know the equation for the temperature:
$T_f=\sqrt[4] {T_0^4 +\frac{P}{e\sigma A}}$
$T_f=\sqrt[4] {300^4 +\frac{50}{(1)(5.67\times10^{-8})((.05)(.005)+(.05)(1\times10^{-4})+(.005)(1\times10^{-4})}}\\T_f=1200 K $
b) We find:
$T_f=T_0+RP=300+(8)(50)=700 \ K$
