Answer
$v =\sqrt{2gh}$
Work Step by Step
We use known equations, including the Bernoulli equation, to find:
$ p_a + \rho gh = p_a + \frac{1}{2}\rho v^2 $
$ \rho gh = \frac{1}{2}\rho v^2 $
$ gh = \frac{1}{2} v^2 $
$v =\sqrt{2gh}$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 15 - Section 15.5 - Applications of Fluid Dynamics - Example - Page 274: 15.6
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