## Essential University Physics: Volume 1 (3rd Edition)

$v =\sqrt{2gh}$
We use known equations, including the Bernoulli equation, to find: $p_a + \rho gh = p_a + \frac{1}{2}\rho v^2$ $\rho gh = \frac{1}{2}\rho v^2$ $gh = \frac{1}{2} v^2$ $v =\sqrt{2gh}$