## Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson

# Chapter 15 - Section 15.4 - Fluid Dynamics - Example - Page 272: 15.5

18 meters

#### Work Step by Step

We solve for the depth to obtain: $d_2 = \frac{v_1w_1d_1}{v_2w_2} = \frac{(2.2)(4.5)(40)}{(6)(3.7)}=18 \ m$

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