Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 14 - Exercises and Problems - Page 262: 28


1.47 kg

Work Step by Step

We know that $v=\frac{l}{t}$ and that v is equal to $\sqrt{\frac{F}{\frac{m}{l}}}$. Thus, we combine these equations to find: $m = \frac{Ft^2}{l} = \frac{78.6\times.585^2}{18.3} = 1.47 \ kg$
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