Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 14 - Exercises and Problems - Page 262: 21


The answer is below.

Work Step by Step

a) We know that the amplitude is the number in front of the cosine, so it is $1.3 \ cm$. b) $ \lambda= \frac{2\pi}{.69}=9.11\ cm$ c) Using the equation, we find $\omega = 31s$. Period equals 2 times pi divided by omega. This gives: $ T = \frac{2\pi}{31}=.2s$ d) $v=\frac{\omega}{k}=\frac{31}{.69}=45\ cm$ e) Negative x direction
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