## Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson

# Chapter 12 - Exercises and Problems - Page 218: 58

#### Answer

The proof is below.

#### Work Step by Step

We call the center of wheel the axis of rotation. Thus, we find: $mgcos\theta=(M+m)gsin\theta$ $mcos\theta-msin\theta=Msin\theta$ $m=\frac{Msin\theta}{cos\theta-sin\theta}$ $m>\frac{Msin\theta}{1-sin\theta}$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.