Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 12 - Exercises and Problems: 58

Answer

The proof is below.

Work Step by Step

We call the center of wheel the axis of rotation. Thus, we find: $mgcos\theta=(M+m)gsin\theta$ $mcos\theta-msin\theta=Msin\theta$ $m=\frac{Msin\theta}{cos\theta-sin\theta}$ $m>\frac{Msin\theta}{1-sin\theta}$
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