#### Answer

$T= 1,456 N $

#### Work Step by Step

We know that the tension is what opposes the torque due to gravity. Thus, we first find the distance from the base of the ligament to each center of mass:
$d_1 = \frac{.28}{cos27}=.31 \ m$
$d_2 =\frac{.76}{cos27}=.85 \ m$
Thus, we find:
$.31(29)(9.81)sin40^{\circ}+.85(68)(9.81)sin63^{\circ}=.85Tsin27^{\circ}$
$T= 1,456 N $