Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 12 - Exercises and Problems - Page 217: 43


.366 mgs

Work Step by Step

We will use the terms of the back of the book's solution, which calls the height s. We know that the mass is given the variable m. Using our knowledge of the geometry of cubes, we know that the height of the center of mass (which in this case is the center of the cube) will be .866s above the ground. Thus, it follows: $\Delta U = .866mgs - .5mgs = .366 mgs$
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