## Essential University Physics: Volume 1 (3rd Edition)

$4.5m$
We know that $N_1=(M+m)g=(95+9.5)\times 9.8=1024N$ We also know that $N_2=\mu N_1$ We plug in the known values to obtain: $N_2=0.42\times 1024=430N$ As $x=\frac{N_2Lsin66-\times\frac{MgL}{2}cos66}{Mgcos66}$ We plug in the known values to obtain: $x=\frac{430\times 5sin66-\frac{9.5\times 9.8}{2}\times 5cos66}{95\times 9.8\times cos66}$ $x=4.5m$