Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 12 - Exercises and Problems: 42

Answer

$4.5m$

Work Step by Step

We know that $N_1=(M+m)g=(95+9.5)\times 9.8=1024N$ We also know that $N_2=\mu N_1$ We plug in the known values to obtain: $N_2=0.42\times 1024=430N$ As $x=\frac{N_2Lsin66-\times\frac{MgL}{2}cos66}{Mgcos66}$ We plug in the known values to obtain: $x=\frac{430\times 5sin66-\frac{9.5\times 9.8}{2}\times 5cos66}{95\times 9.8\times cos66}$ $x=4.5m$
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