## Essential University Physics: Volume 1 (3rd Edition)

$9.2\times10^{26}N\cdot m$
Using the trendline, we find that the torque is equal to $.0039\times10^{37}kgm^2/s/yr$. From this, we find that the torque is: $=\frac{.0029\times10^{37}kgm^2/s/yr}{31536000}=9.2\times10^{26}N\cdot m$