Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 11 - Exercises and Problems: 63

Answer

$9.2\times10^{26}N\cdot m$

Work Step by Step

Using the trendline, we find that the torque is equal to $.0039\times10^{37}kgm^2/s/yr$. From this, we find that the torque is: $=\frac{.0029\times10^{37}kgm^2/s/yr}{31536000}=9.2\times10^{26}N\cdot m$
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