# Chapter 11 - Exercises and Problems - Page 203: 63

$9.2\times10^{26}N\cdot m$

#### Work Step by Step

Using the trendline, we find that the torque is equal to $.0039\times10^{37}kgm^2/s/yr$. From this, we find that the torque is: $=\frac{.0029\times10^{37}kgm^2/s/yr}{31536000}=9.2\times10^{26}N\cdot m$

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