Answer
$6.98\times10^6\ m$
Work Step by Step
We use conservation of angular momentum:
$(2.91\times10^{-6}(\frac{2}{5})mR^2=(.048)(\frac{2}{5})(.6m)(xR)^2$
$x=.01$
Thus, we find:
$R=.01R_{sun}=6.98\times10^6\ m$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 11 - Exercises and Problems - Page 203: 62
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