Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 11 - Exercises and Problems - Page 203: 62


$6.98\times10^6\ m$

Work Step by Step

We use conservation of angular momentum: $(2.91\times10^{-6}(\frac{2}{5})mR^2=(.048)(\frac{2}{5})(.6m)(xR)^2$ $x=.01$ Thus, we find: $R=.01R_{sun}=6.98\times10^6\ m$
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