## Essential University Physics: Volume 1 (3rd Edition)

a) $v = \Delta x \sqrt{\frac{k}{m}}$' b) $\omega = \frac{m\Delta x \sqrt{\frac{k}{m}}b}{I}$
a) We know energy is conserved, so: $\frac{1}{2}k\Delta x^2 = \frac{1}{2}mv^2 \\ v = \Delta x \sqrt{\frac{k}{m}}$ b) We know angular momentum is conserved, so: $mvb=I\omega$ $m\Delta x \sqrt{\frac{k}{m}}b=I\omega$ $\omega = \frac{m\Delta x \sqrt{\frac{k}{m}}b}{I}$