Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 11 - Exercises and Problems: 56

Answer

a) 1.61 b) The day increases by a factor of 2.221.

Work Step by Step

a) We find: $\frac{R}{R_0}=(\sqrt[3] {\frac{1}{1-.8^3}})^2 = 1.61$ b) Using the equation for the volume of a sphere and the equation for moment of inertia, we find that $r^2\times r^3 =r^5$. Consequently, we can find the ratios of periods to be: $=(1.27)^5\times(1-.8^5)=2.221$ The day increases by a factor of 2.221.
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