Answer
Please see the work below.
Work Step by Step
The given distance is
$d=2.4\times 10^{22}m$
$d=2.4\times 10^{1}\times 10^{21}m$
$d=24\times 10^{21}m$
We know that $10^{21}=Zetta \space denoted \space by \space Z$
$\implies d=24Zm$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 1 - Exercises and Problems - Page 12: 31
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