## Essential University Physics: Volume 1 (3rd Edition)

The given distance is $d=2.4\times 10^{22}m$ $d=2.4\times 10^{1}\times 10^{21}m$ $d=24\times 10^{21}m$ We know that $10^{21}=Zetta \space denoted \space by \space Z$ $\implies d=24Zm$