Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 1 - Exercises and Problems: 31

Answer

Please see the work below.

Work Step by Step

The given distance is $d=2.4\times 10^{22}m$ $d=2.4\times 10^{1}\times 10^{21}m$ $d=24\times 10^{21}m$ We know that $10^{21}=Zetta \space denoted \space by \space Z$ $\implies d=24Zm$
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