Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 1 - Exercises and Problems: 14

Answer

Please see the work below.

Work Step by Step

We can find the required distance as $d=vt$ We plug in the known values to obtain: $d=(3.00\times 10^8)(1\times 10^{-9})$ $d=0.300m$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.