Answer
W = Fd = (500 N)(2.2 m) = $1100 N \cdot m = 1100 J$
This also the gain in PE.
Work Step by Step
W= Fd
(500N)(2.2m) = 1100 Joules
1100 Joules is the gain of potential energy of the barbell when it is lifted to 2.2 meters off the floor.
Conceptual Physics (12th Edition)
by Hewitt, Paul G.
Published by
Addison-Wesley
ISBN 10:
0321909100
ISBN 13:
978-0-32190-910-7
Chapter 7 - Plug and Chug - Page 127: 31
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