Answer
$$KE = \frac{1}{2}mv^{2} = \frac{1}{2}(84 kg)(10 m/s)^{2} = 4200 J$$
Conceptual Physics (12th Edition)
by Hewitt, Paul G.
Published by
Addison-Wesley
ISBN 10:
0321909100
ISBN 13:
978-0-32190-910-7
Chapter 7 - Plug and Chug - Page 127: 37
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