Answer
A meterstick moving at $99.5\%$ the speed of light would appear to be one-tenth its original length.
Work Step by Step
Let $L_{o}$ represent the original, proper length, and L the measured length of the moving object.
$$L = L_{o} \sqrt{1-\frac{ v^{2} } { c^{2} }} $$
$$L = L_{o} \sqrt{1-0.995^{2}} = \frac{1}{10} L_{o} $$
This is discussed on page 676.
