Conceptual Physics (12th Edition)

Published by Addison-Wesley
ISBN 10: 0321909100
ISBN 13: 978-0-32190-910-7

Chapter 35 - Reading Check Questions (Comprehension): 14


See below.

Work Step by Step

Gamma $= \gamma = \frac{1}{\sqrt{1-\frac{ v^{2} } { c^{2} }}}$. This is never less than 1 because $\frac{v^{2}}{c^{2}}$ is always positive and less than or equal to 1. The denominator is always positive and less than 1, so its inverse (or reciprocal) is always greater than or equal to 1. This is discussed on page 666.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.