Answer
a). $(1)$ a cold day
b). $1.9\times10^{5}N$
Work Step by Step
a). The correct choice is (1), a cold day, because tracks expand when temperature increases.
b). L=8m,
A=$2.5\times10^{-3}m^{2}$
$\Delta L=3.0\times 10^{-3}m$
Y=$210\times 10^{9}Pa$
So, $\frac{F}{A}=\frac{Y\Delta L}{L}$
or, $F=\frac{Y\Delta L A}{L}=1.9\times10^{5}N$ (after inserting the above values)