College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 9 - Solids and Fluids - Learning Path Questions and Exercises - Exercises - Page 349: 9

Answer

a). $(1)$ a cold day b). $1.9\times10^{5}N$

Work Step by Step

a). The correct choice is (1), a cold day, because tracks expand when temperature increases. b). L=8m, A=$2.5\times10^{-3}m^{2}$ $\Delta L=3.0\times 10^{-3}m$ Y=$210\times 10^{9}Pa$ So, $\frac{F}{A}=\frac{Y\Delta L}{L}$ or, $F=\frac{Y\Delta L A}{L}=1.9\times10^{5}N$ (after inserting the above values)
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