Answer
$1.07\times10^{11}Pa$
Work Step by Step
Young's modulus $Y=\frac{FL}{A\Delta L}=\frac{6\times 9.8\times2}{3.14\times \frac{1}{4}\times10^{-6}\times1.4\times 10^{-3}}=1.07\times 10^{11}Pa$
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