#### Answer

a). $513N$
b). $0.151m/s$

#### Work Step by Step

a). Change in velocity $=47+122=169mi/hr=75.5m/s$
Therefore, $F=ma=m\frac{\Delta v}{\Delta t}=0.17\frac{75.5}{0.025}=513N$
b). $v=a_{g}t=\frac{F}{m_{g}}t=\frac{513}{85}0.025=0.151m/s$

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Published by
Pearson

ISBN 10:
0-32160-183-1

ISBN 13:
978-0-32160-183-4

a). $513N$
b). $0.151m/s$

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