College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 4 - Force and Motion - Learning Path Questions and Exercises - Exercises - Page 140: 85

Answer

a). $-8.25m/s^{2}$ b). $0.841$ c). $31m/s$

Work Step by Step

a). $a=\frac{v^{2}-u^{2}}{2S}=\frac{-29.15^{2}}{2\times51.5}=-8.25m/s^{2}$ b). Coefficient of friction $=-\frac{a}{g}=0.841$ c). initial velocity = $\sqrt (v^{2}-2aS)=\sqrt (0^{2}-2\times(-8.25)\times57.3)=31m/s$
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