Answer
$7.0\times10^{5}\,N$
Work Step by Step
Mass $m=2.0\times10^{5}\,kg$
Acceleration $a=3.5\,m/s^{2}$
$F_{net}=ma=2.0\times10^{5}\,kg\times3.5\,m/s^{2}=7.0\times10^{5}\,N$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 4 - Force and Motion - Learning Path Questions and Exercises - Exercises - Page 135: 14
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