College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 4 - Force and Motion - Learning Path Questions and Exercises - Exercises - Page 135: 12

Answer

$4.0\,ms^{-2}$

Work Step by Step

According to Newton's second law of motion, $F=ma$ or $a=\frac{F}{m}$ Given: F= 6.0 N and m=1.5 kg Then object's acceleration $a=\frac{6.0\,N}{1.5\,kg}=4.0\,ms^{-2}$
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