Answer
a). The right answer is (3) decreases, because if energy increases, the mass increases, and the range is inversely proportional to the mass.
b). $1.98\times10^{-16}m$
Work Step by Step
a). The right answer is (3) decreases, because if energy increases, the mass increases, and the range is inversely proportional to the mass.
b). $R=\frac{h}{2\times pi\times m_{m}c}$
Also, $\Delta E=m_{m}c^{2}$
So, $R=\frac{hc}{2\times pi \times \Delta E }$, where $\Delta E=1 GeV=1.6\times10^{-10} J$
$R=\frac{6.634\times10^{-34}\times3\times10^{8}}{2\times pi \times 1.6\times10^{-10}}$
Hence, calculating for R, $R=1.98\times10^{-16}m$
