College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 30 - Nuclear Reactions and Elementary Particles - Learning Path Questions and Exercises - Exercises - Page 1031: 23

Answer

In a $beta^{+}$ decay, $P^{A}_{Z}=D^{A}_{Z-1}+e^{0}_{+1}$ so, $Q=(m_{p}-m_{D}-m_{e})c^{2}=[{(m_{p}+Zm_{e})-[m_{D}+(Z-1)m_{e}]-2m_{e}}]c^{2}=(M_{p}-M_{D}-2m_{e})c^{2}$ Hence, proved.

Work Step by Step

In a $beta^{+}$ decay, $P^{A}_{Z}=D^{A}_{Z-1}+e^{0}_{+1}$ so, $Q=(m_{p}-m_{D}-m_{e})c^{2}=[{(m_{p}+Zm_{e})-[m_{D}+(Z-1)m_{e}]-2m_{e}}]c^{2}=(M_{p}-M_{D}-2m_{e})c^{2}$ Hence, proved.
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