College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 3 - Motion in Two Dimensions - Learning Path Questions and Exercises - Exercises - Page 98: 38

Answer

Final displacement vector = $(-8.54x+25.86y)\,m$ And $R=27.3m$, $\theta=72.5^{\circ}$ above negative x-axis.

Work Step by Step

The y-displacement =$20cos60^{\circ}+30-20cos45^{\circ}=25.86m$ The x-displacement= $20cos30^{\circ}-40+20cos45^{\circ}=-8.54m$ So, final displacement vector = $(-8.54x+25.86y)\,m$ And $R=27.3m$, $\theta=72.5^{\circ}$ above negative x-axis.
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