College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 3 - Motion in Two Dimensions - Learning Path Questions and Exercises - Exercises - Page 98: 28

Answer

a) $(-4x+8y)$ m/s b) $8.94\,m/s$

Work Step by Step

a) All components of velocity vector of object 2 will be twice and opposite of that of object 1. So, velocity of object 2 = $(-4x+8y)$ m/s b) Speed of object 2 = $\sqrt (4^{2}+8^{2})=8.94 m/s$
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