#### Answer

(a) For $\theta<45^{\circ}$, the horizontal component is greater than the vertical component.
(b) For $\theta=37^{\circ}$, the horizontal component is $27.95\,\mathrm{m/s}$ and the vertical component is $21.06\,\mathrm{m/s}$.

#### Work Step by Step

A velocity $v$ directed at an angle $\theta$ above horizontal has the components -
$v_x=v\cos\theta$
$v_y=v\sin\theta$.
(a) For $\theta<45^{\circ}$, $\cos\theta>\sin\theta$.
Thus, the horizontal velocity component is greater than the vertical velocity component.
(b) For $\theta=37^{\circ}$, initial velocity components -
$v_x=35\cos37^{\circ}=27.95\,\mathrm{m/s}$
$v_y=35\sin37^{\circ}=21.06\,\mathrm{m/s}$.