College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 29 - The Nucleus - Learning Path Questions and Exercises - Exercises - Page 998: 18

Answer

(a) $6.76\times10^{-5}\,Ci$ (b) $2.50\times10^{6}\,Bq$

Work Step by Step

(a) Activity R= $2.50\times10^{6}\,decays/s=2.50\times10^{6}\,decays/s\times\frac{1\,Ci}{3.70\times10^{10}\,decays/s}$ $=6.76\times10^{-5}\,Ci$ (b) 1 decay/s= 1 Bq. Therefore, $2.50\times10^{6}\,decays/s=2.50\times10^{6}\,Bq$
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