Answer
Stopping voltage of the photoelectron is affected by the workfunction.
Work Step by Step
hf= $K_{max} + \phi_{0}$ .............equation 1
here hf is Energy of incident photon (f is frequency of light)
$K_{max}$ is maximum kinetic energy of emitted photoelectron
$\phi_{0}$ is work function of the material (minimum energy needed to free the electron.
Stopping voltage $V_{0}$ is a voltage needed to stop photoelectron of maximum kinetic energy $K_{max}$ .thus
$V_{0} = \frac{K_{max}}{e}$ equation (2)
putting $K_{max} =hf -\phi_{0}$ in eqution (2) will give
$V_{0} = \frac{hf -\phi_{0}}{e}$... equation (3)
this equation suggests that stopping voltage is affected by work function. For light of the same incident stopping potential will be more for material with lower work function.
