## College Physics (7th Edition)

$3.0cm$, real and inverted.
$ho=6cm$ $do=75cm$ $R=50cm$ So, $f=R/2=25cm$ $\frac{1}{do}+\frac{1}{di}=\frac{1}{f}$ or, $\frac{1}{di}=\frac{1}{25}-\frac{1}{75}=\frac{2}{75}$ or, $di=37.5cm$ $M=|\frac{-37.5}{75}|=0.5$ Thus, the image is inverted because of (-) sign, and size is = $0.5\times 6=3cm$