College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 23 - Mirrors and Lenses - Learning Path Questions and Exercises - Exercises - Page 806: 19


$3.0cm$, real and inverted.

Work Step by Step

$ho=6cm$ $do=75cm$ $R=50cm$ So, $f=R/2=25cm$ $\frac{1}{do}+\frac{1}{di}=\frac{1}{f}$ or, $\frac{1}{di}=\frac{1}{25}-\frac{1}{75}=\frac{2}{75}$ or, $di=37.5cm$ $M=|\frac{-37.5}{75}|=0.5$ Thus, the image is inverted because of (-) sign, and size is = $0.5\times 6=3cm$
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