#### Answer

a) The image is (1) real,, (2) inverted, (3) reduced.
b) 66.7 cm infront of the mirror.
c) lateral magnification is 0.667.

#### Work Step by Step

a) We will see that the rays converge below the x-axis making the new image inverted (therefore real) and reduced in size because the new image is smaller than the original object size.
b) By the spherical mirror equation, $\frac{1}{do}+\frac{1}{di}=\frac{1}{f}$
Thus, $\frac{1}{100}+\frac{1}{di}=\frac{1}{40}$
So, the image is 66.7 cm in front of the mirror.
c) Magnification = $|\frac{66.7}{100}|=0.667$