## College Physics (7th Edition)

$42^{\circ}$ or $138^{\circ}$
Flux = $BAcos\theta$ , $B=0.15T, A=0.1256m^{2}$ Since the magnitude of flux is given, its sign can be positive or negative; From above equation, $cos\theta=\frac{1.4\times10^{-2}}{0.15\times 0.1256}=0.7430$ Thus, $\theta=42^{\circ}$ or $138^{\circ}$